PX is equal to 8 x square - 19 x minus 15
Attachments:
Answers
Answered by
12
Step-by-step explanation:
Given -
p(x) = 8x² - 19x - 15
To Find -
- Zeroes of the polynomial.
- Verify the relation between the zeroes and the coefficient of the polynomial.
Now,
8x² - 19x - 15
= 8x² - 24x + 5x - 15
(By middle term splitt)
= 8x(x - 3) + 5(x - 3)
= (8x + 5)(x - 3)
Then,
Zeroes are -
8x + 5 = 0 and x - 3 = 0
- x = - 5/8 and x = 3
Let α = 3 and β = -5/8
Verification -
α + β = -b/a
= 3 + (-5/8) = -(-19)/8
= 3 - 5/8 = 19/8
= 24 - 5/8 = 19/8
= 19/8 = 19/8
LHS = RHS
And
αβ = c/a
= 3 × -5/8 = -15/8
= -15/8 = -15/8
LHS = RHS
Hence,
Verified..
Answered by
2
x = 3
x = -5/8
- p(x) = 8x² - 19x - 15
- zero of the polynomial
- verify relation between the zeroes and the coefficient of the polynomial.
8x² - 19x - 15 = 0
8x² - 24x + 5x - 15 = 0
8x(x - 3) + 5(x - 3)
(8x + 5)(x - 3)
8x + 5 = 0
x = -5/8
x - 3 = 0
x = 3
Let α = 3 and β = -5/8
α + β = -b/a
3 + (-5/8) = -(-19)/8
3 - 5/8 = 19/8
24 - 5/8 = 19/8
19/8 = 19/8
αβ = c/a
3 × -5/8 = -15/8
-15/8 = -15/8
Similar questions