Question

PX is equal to K x square minus root 2 X + 1​

Answer 1

Step-by-step explanation:

P(x)=kx^2 - root2x + 1 X-1 is a factor That means P(1)=0 kx^2 - root2x +1=0 k(1)^2 - root2(1) + 1=0 k - root2 + 1=0 k- root2=-1 k=-1+root2 as root2=(approx.)1.414 k=-1+1.414 k=0.414(apprx.)