(px+qy)(A.x-by)=???????,
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Answered by
23
Answer :
Now, (px + qy) (Ax - by)
= (px × Ax) - (px × by) + (qy × Ax) - (qy × by)
= Apx² - bpxy + Aqxy - bqy²
= Apx² + (Aq - bp)xy - bqy²
#MarkAsBrainliest
Now, (px + qy) (Ax - by)
= (px × Ax) - (px × by) + (qy × Ax) - (qy × by)
= Apx² - bpxy + Aqxy - bqy²
= Apx² + (Aq - bp)xy - bqy²
#MarkAsBrainliest
Answered by
18
Hi there!
(px + qy) (Ax - by)
= [ px × Ax ] - [ px × by ] + [ qy × Ax ] - [ qy × by ]
= Apx² - bpxy + Aqxy - bqy²
= Apx² + (Aq - bp) xy - bqy²
Hope it helps! :)
(px + qy) (Ax - by)
= [ px × Ax ] - [ px × by ] + [ qy × Ax ] - [ qy × by ]
= Apx² - bpxy + Aqxy - bqy²
= Apx² + (Aq - bp) xy - bqy²
Hope it helps! :)
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