Question

px+qy=p-q,qx-py=p+q
Find the value of x and y.

Answer 1

Given pair of linear equations,
px+qy=p-q..............................................1

qx-py=p+q.............................................2
solving eq1 we get,
px=p-q-qy

x=(p-q-qy)/p..........................................3
Putting eq3 in eq2 we get,
q{(p-q-qy)/p}-py=p+q

(qp-q²-q²y)/p-py=p+q

qp-q²-q²y-p²y=p²+qp

-y(q²+p²)=p²+q²

-y=1

y=-1........................................................4
Putting eq4 in eq3 we get,
x=(p-q+q)/p

x=p/p

x=1





Hence value of x=1 and y=-1.

Answer 2

y=-1
from eq 1
px+qy=p-q
px-q=p-q
px=p-q+q
x=p/p
x=1