Question

px+qy=r;qx+py=n; 1÷(x+y)=?​

Answer 1

Answer:

Therefore the answer is $\frac{1}{x+y} = \frac{p+q}{r+n}$

Step-by-step explanation:

In the question we are given that

px+qy=r

qx+py=n

If we add these two we will get

px+qy+qx+py=r+n

or, p(x+y) +q(x+y)=r+n

or, (p+q)(x+y) = r+n

$x+y=\frac{r+n}{p+q}$

Now in the question we are told to find the value of $\frac{1}{x+y}$

To find this we just need to find the inverse of what we have

ie., $\frac{1}{x+y} = \frac{p+q}{r+n}$