Question

px = root of x3 +1 is not a polynomial. explain why​

Answer 1

Answer:

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Step-by-step explanation:

It is not a polynimial bybthe definition of a polynomial.

But what if it is equal to some polynimial as a functions on . Notice that polynomials are equal to each other iff all their coefficients are equal (this is not true for polynomials over finite fields by the way).

We get:

. But as soon as you try to check the degree of Q you find out that 1 is too small and 2 is too big. (Either we do not get the term with or we get the term with we should not have).

Thus it cannot be a polynomial even as a function.

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2 comments from Bernard Leak

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Answer 2

Answer:

Your question is this:

p(x) =

$\sqrt{ {x}^{3} } + 1$

p(x) is not a polynomial because degree of a polynomial is always a whole number ... here degree is 3/2 which is not a whole number. Hence p(x) is not a polynomial