Question

px(x-2)+6=0 determine value of p which has real roots

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Answer 1

Answer:

p=6

Step-by-step explanation:

px(x-2)+6=0

px^2-2px+6=0

for real roots D>=0

4p^2 - 24p=0

p^2 - 6p=0

p(p-6)=0

p=6

Answer 2

here is your answer, mate