PX(x-3)+9=0 find value of p
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★ QUADRATIC RESOLUTION ★
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Helloo!!
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
since, p=4
hope it helps
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
since, p=4
hope it helps
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