Math, asked by BlackCell8929, 1 year ago

px2-14x+18=0 are 6 time of number

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Answered by navneet200477
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Find the value of p, for which one root of the quadratic equation px^2 – 14x + 8 = 0 is 6 times the other. Mathematics CBSE class 10 2017

Find the value of p, for which one root of the quadratic equation px^2 – 14x + 8 = 0 is 6 times the other.

Asked by:tarun101

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Answers

Given

px^2-14x+8=0

let a and b be the roots of the equation

b=6a

sum of roots = -b/a

product of roots = c/a

here a=p , b=-14 , c=8

a+b=14/p

ab=8/p

a+6a=14/p

7a=14/p

a=2/p

a*6a=8/p

6a^2=8/p

3a^2=4/p

3*(2/p)^2=4/p

3*4/p^2=4/p

p=3

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