px² +(2q_p²) x_2pq, p =/0 please solve
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Given : px² + ( 2q - p² )x - 2pq = 0
px² + 2qx - p²x - 2qp = 0
px² - p²x + 2qx - 2pq = 0
px ( x - p ) + 2q ( x - p ) = 0
( px + 2q ) ( x - p ) = 0
Using Zero Product Rule
px + 2q = 0 and x - p = 0
x = - 2q / p and x = p
px² + 2qx - p²x - 2qp = 0
px² - p²x + 2qx - 2pq = 0
px ( x - p ) + 2q ( x - p ) = 0
( px + 2q ) ( x - p ) = 0
Using Zero Product Rule
px + 2q = 0 and x - p = 0
x = - 2q / p and x = p
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