Math, asked by aman7892, 1 year ago

px² +(2q_p²) x_2pq, p =/0 please solve​

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Answered by 22072003
2
Given : px² + ( 2q - p² )x - 2pq = 0

px² + 2qx - p²x - 2qp = 0

px² - p²x + 2qx - 2pq = 0

px ( x - p ) + 2q ( x - p ) = 0

( px + 2q ) ( x - p ) = 0

Using Zero Product Rule

px + 2q = 0 and x - p = 0

x = - 2q / p and x = p

aman7892: आपका answer गलत है
aman7892: इसका answer है p,-2q/p
22072003: Corrected ✓
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