Question

px2+2x+q=0 has two roots -1 and -2 then the value of q-p is​

Answer 1

Step-by-step explanation:

The roots here are the values of x.

so, putting the value of x=-1

2p(-1) +2(-1) + q =0

-2p -2 +q = 0

➡️ q-2p = 2 ........... 1

now, putting x=-2

2p(-2)+2(-2)+q=0

-4p-4+q=0

➡️q-4p = 4 ........... 2

from EQ. 1 and 2

p = -1

q = 0

so, q-p =1