Math, asked by poojapmasari, 21 days ago

px²+4x+0 find whether it has equal roots

Answers

Answered by sabaqueen86
0

Answer:

From equation (i),

px

2

−4x+3=0

a=p,b=−4 and c=3

If the roots of this equation are equal and real, then D=0.

Therefore,

D=b

2

−4ac=0

(−4)

2

−4×p×3=0

16−12p=0

12p=16

p=

3

4

So, the value of p is

3

4

.

From equation (ii),

x

2

+(p−3)x+p=0

a=1,b=(p−3) and c=p

If the roots of this equation are equal and real, then D=0.

Therefore,

D=b

2

−4ac=0

(p−3)

2

−4×1×p=0

p

2

+9−6p−4p=0

p

2

−10p+9=0

p

2

−9p−p+9=0

p(p−9)−1(p−9)=0

(p−1)(p−9)

p=1,9

So, the values of p is 1,9.

Hence, this is correct answer.

Answered by ganeshbabu5847a
0

Answer:

Answer

Open in answr app

From equation (i),

px2−4x+3=0

a=p,b=−4 and c=3 

If the roots of this equation are equal and real, then D=0.

Therefore,

D=b2−4ac=0

(−4)2−4×p×3=0

16−12p=012p=16

p=34

So, the value of p is 34.

From equation (ii),

x2+(p−3)x+p=0

a=1,b=(p−3) and c=p 

If the roots of this equation are equal and real, then D=0.

Therefore,

D=b2−4ac=0

(p−3)2−4×1×p=0

p2+9−6p−4p=0

p2−10p+9=0

p2−9p−p+9=0

p(p−9)−

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