px²+4x+0 find whether it has equal roots
Answers
Answer:
From equation (i),
px
2
−4x+3=0
a=p,b=−4 and c=3
If the roots of this equation are equal and real, then D=0.
Therefore,
D=b
2
−4ac=0
(−4)
2
−4×p×3=0
16−12p=0
12p=16
p=
3
4
So, the value of p is
3
4
.
From equation (ii),
x
2
+(p−3)x+p=0
a=1,b=(p−3) and c=p
If the roots of this equation are equal and real, then D=0.
Therefore,
D=b
2
−4ac=0
(p−3)
2
−4×1×p=0
p
2
+9−6p−4p=0
p
2
−10p+9=0
p
2
−9p−p+9=0
p(p−9)−1(p−9)=0
(p−1)(p−9)
p=1,9
So, the values of p is 1,9.
Hence, this is correct answer.
Answer:
Answer
Open in answr app
From equation (i),
px2−4x+3=0
a=p,b=−4 and c=3
If the roots of this equation are equal and real, then D=0.
Therefore,
D=b2−4ac=0
(−4)2−4×p×3=0
16−12p=012p=16
p=34
So, the value of p is 34.
From equation (ii),
x2+(p−3)x+p=0
a=1,b=(p−3) and c=p
If the roots of this equation are equal and real, then D=0.
Therefore,
D=b2−4ac=0
(p−3)2−4×1×p=0
p2+9−6p−4p=0
p2−10p+9=0
p2−9p−p+9=0
p(p−9)−