Question

Pythagoras property of a right Triangle.
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Answer 1

$hypotenuse {}^{2} = base {}^{2} + altitude {}^{2}$

for example,

find hypotenuse of a ∆ with base 3 and altitude 4 cm

${hypotenuse}^{2} = {3}^{2} + {4}^{2}$

${hyp}^{2} = 9 + 16$

$hypotenuse = \sqrt{9 + 16}$

$hyp = \sqrt{25}$

$\sqrt{25} = 5cm$

hope it is helpful....

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