pythagoras =root 26 square-24square
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Answer:
10
Step-by-step explanation:
5, 12 and 13 are a Pythagorean triplet., such that
5^2 + 12^2 = 13^2.
if a, b, c form Pythagorean triplet, then na, nb and nc also form a Pythagorean triplet.
Here a = 5 , b = 12, c = 13 and n = 2.
nc ^2 = na^2 + nb^2
= (2 * 5) ^ 2 + (2 * 12)^2
= (2 * 13)^2
Therefore , clearly , 26^2 = 10^2 + 24^2 or
10 = √ ((26)^2 - (24)^2).
Hope this helps.
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