pythagoras theorem find value of x
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HEY MATE!
IN RIGHT TRIANGLE EDF, RIGHT ANGLE AT D
EF^2=DE^2+DF^2
(17)^2=DE^2 + 8^2
289-64=DE^2
DE^2=225
DE=15cm
I HOPE IT HELPS YOU!
IN RIGHT TRIANGLE EDF, RIGHT ANGLE AT D
EF^2=DE^2+DF^2
(17)^2=DE^2 + 8^2
289-64=DE^2
DE^2=225
DE=15cm
I HOPE IT HELPS YOU!
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