pythagoras theorem geometry.
If you can do it on a copy.
Two different sums
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Answer:
Hope it helps :)
Step-by-step explanation:
Let the d length be x + y.
So,
(26)^2 = (24)^2 + y^2
676 = 576 + y^2
676 - 576 = y^2
100 = y^2
√100 = y
10cm = y...........................eq 1
(30)^2 = (24)^2 + x^2
900 = 576 + x^2
900 - 576 = x^2
324 = x^2
√324 = x
18 cm = x...........................eq 2
There d cm = x + y = 10 + 18 = 28cm
Similarly you can solve the second sum :)
Answered by
1
Step-by-step explanation:
hope it helps........
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