pythagoras triplet of 6 with complete solution.
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Answers
Answer:
Pythagorean Triples
Pythagorean triples are formed by positive integers a, b and c, such that a2 + b2 = c2. We may write the triple as (a, b, c)
For example, the numbers 3, 4 and 5 form a Pythagorean Triple because 32 + 42 = 52. There are infinitely many Pythagorean triples.
Some examples are
( 3 , 4 , 5 ) ( 5, 12, 13) ( 7, 24, 25) ( 8, 15, 17)
( 9, 40, 41) (11, 60, 61) (12, 35, 37) (13, 84, 85)
(16, 63, 65) (20, 21, 29) (28, 45, 53) (33, 56, 65)
(36, 77, 85) (39, 80, 89) (48, 55, 73) (65, 72, 97)
Families of Pythagorean Triples
If we multiply each number of a Pythagorean triple by the same number, we form another Pythagorean triple.
For example, (6, 8, 10) is a family of the Pythagorean triple (3, 4, 5) because it can be obtained by 2 × 3 = 6, 2 × 4 = 8, 2 × 5 = 10. If we multiply (3, 4, 5) by 3, we get another triple (9, 12, 15). This can be repeated with different multiples.
Similarly, the family for (5, 12, 13) would be (10, 24, 26), (15, 36, 39) and so on.
Step-by-step explanation:
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Given ,
To find Pythagoras triplet whose one member is 6
We have , 2m , m²-1 and m²+1 .
So let's try ,
m²-1 = 6
m² = 7
m = √7
The value of m won't be an integer .
So let's try for ,
2m = 6
m = 3
Here , the value of m will be an integer , so m = 3 is possible .
Therefore ,
2m = 6
m²-1 = 3²-1 = 8
m²+1 = 3²+1 = 10
Thus , the Pythagoras triplet is 6,8 and 10 .
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