Pythagorean triplet for root 2 is
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Pythagorean triplet
√2= 2×2=4
First number=2m=2× 4=8
Second number=4-1=3
Third number=4+1=5
therefore, Ans=8,5,3
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Answer:
the required Pythagorean triplet : 3,4 and 5
Step-by-step explanation:
given,
√2
converting into a rational number ,
√2×√2 = 2
now ,
the first number = 2m = 2×2 = 4
the second number = m²-1 = 2²-1=3
the third number = m²+1=2²+1=5
proof: by Pythagoras theorem ,
we know that : h²=p²+b²
therefore ,
LHS : 5²=25
RHS: 3²+4²=25
Since, LHS = RHS
therefore , the triplet is achieved
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