pythagorean triplet of 8cm, 5cm, 10cm
Answers
Answered by
0
Answer:
ANSWER
Let H=10 cm,P=8 cm,B=6 cm.
By Pythagoras theorem,
H2=P2+B2
102=82+62
100=64+36
100=100
Hence, it is right angled triangle.
Answered by
1
Given:-
⠀⠀⠀⠀
- 8cm , 5cm , 10cm
⠀⠀⠀⠀
To find :-
⠀⠀⠀⠀
- Find Weather it is a Pythagoras triplet or not
⠀⠀⠀⠀
Concept used :-
⠀⠀
- square of the largest numbers of 3 is equal to the sum.of square of other 2 numbers . such numbers are together known as Pythagoras triplet
⠀⠀⠀⠀
Solution :-
⠀⠀⠀⠀
- Finding the greatest number
⠀⠀
8cm > 5cm
⠀⠀⠀⠀
10cm > 8cm
⠀⠀⠀⠀
- Therefore , 10cm is greatest
⠀⠀⠀⠀
10² | 8² + 5²
⠀⠀
100 | 64 + 25
⠀⠀⠀⠀
100 | 89
⠀⠀⠀⠀
100 ≠ 89
⠀⠀⠀⠀
- Therefore it is not a Pythagoras triplet
Similar questions