Question

python class 12 computer science

note - without using inbuilt function

WAP to create a nested list of numbers and display menu
a) Maximum in each row
b) Sum in each row
c) Minimum in each column
d) Average in each column​

Answer 1

$\textsf{\large{\underline{Solution}:}}$

The given problem is solved using language - Python.

matrix=[]

rows=int(input('Enter the number of rows for the matrix: '))

columns=int(input('Enter the number of columns for the matrix: '))

print('\nEnter the matrix elements...')

for i in range(rows):

   x=[]

   for j in range(columns):

       x.append(int(input(f'a[{i}][{j}] = ')))

   matrix.append(x)

print('\nGiven Matrix:')

for i in matrix:

   for j in i:

       print(j,end=' ')

   print()

print('\n1. Maximum value in each row.')

print('2. Sum of each row.')

print('3. Minimum in each column.')

print('4. Average in each column.')

choice=int(input('\nEnter your choice: '))

if choice==1:

   print()

   for i in range(rows):

       max=matrix[i][0]

       for j in range(columns):

           if matrix[i][j]>max:

               max=matrix[i][j]

       print('Largest Element in Row',i+1,'is:',max)

elif choice==2:

   print()

   k=1

   for i in matrix:

       sum=0

       for j in i:

           sum+=j

       print('Sum of elements in row',k,'is:',sum)

       k+=1

elif choice==3:

   print()

   for i in range(columns):

       cols=[m[i] for m in matrix]

       min=cols[0]

       for j in range(1,rows):

           if cols[j]<min:

               min=cols[j]

       print('Minimum element in column',i+1,'is:',min)

elif choice==4:

   print()

   for i in range(columns):

       cols=[m[i] for m in matrix]

       sum=0

       for j in cols:

           sum+=j

       sum/=rows

       print('Average of elements in column',i+1,'is:',sum)

else:

   print('Invalid Choice.')

Note: No inbuilt functions are used. The given co‎de calculates all the operations according to the user's choice. For an invalid choice, an error message is displayed.