Question

Python code for the following series.

1 2 3 4 5 1 3 5 7 9 1 4 7 10 13 1 5 9 13 17....N terms. ​

Answer 1

Answer:

def series(j):

   i=1

   sum=0

   c=1

   while i<6:

       sum=sum+c

       c=j

       print(sum,end=" ")

       i+=1

j=1

while j<5:

   series(j)

   j+=1

Explanation:

Answer 2

Question:-

• Python Code to print this series
• 1 2 3 4 5 1 3 5 7 9 1 4 7 10 13 1 5 9 13 17....N terms.

It is a very interesting question....only a logic is required to understand this series.

In first 5 terms, the difference is 0(1,2,3,4,5)

In next five terms, difference is 1(1,3,5,7,9)

In next five terms, difference is 2(1,4,7,10)

And after each 5th term the number returns to 1 and the difference increases numerically

Since we found this logic, now code which I am going to write is based on this logic.

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Code:-

#code written by@swetank232894

n=(int)(input("Enter a number:"))

a,b,c=1,1,1

for i in range(1,n+1):

print(a,end=" ")

a+=b

c+=1

if(c>5):

c=1

b+=1

a=1

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Variable Description:-

1. i:- loop variable
2. a :- to calculate and print the terms
3. b:- to add the difference to the variable a
4. c:- counter variable
5. n:- to accept Number of terms from the user

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•Output Attached