Computer Science, asked by anindyaadhikari13, 3 months ago

Python code for this pattern.
1
0 1
0 1 0
1 0 1 0
1 0 1 0 1

Thank you :)

Answers

Answered by Oreki

k = 1

for i in range(0, 5 + 1):

for j in range(1, i + 1):

print("0" if k % 2 == 0 else "1", end="")

k += 1

print( )

anindyaadhikari13: c=1
n=int(input("Enter: "))
for i in range(n):
for j in range(i+1):
print(c%2,end=" ")
c+=1
print()

anindyaadhikari13: This is another approach I tried.

anindyaadhikari13: Thanks for your help @Oreki :)

BrainlyProgrammer: Gr8 Answer!!

Oreki: Thanks for the smaller code @anindyaadhikari13!

Oreki: Thanks @swetank232894 too!

Anonymous: Awesome !! ^_^

Oreki: Thanks @CaptainInvictus!

RockingStarPratheek: Appreciable Work Done, Keep it Up

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