Question

Python program to check and print the neon number upto 1000 using function. ​

Answer 1

Answer:

# Python program to check and print 

# Neon Numbers upto 10000

  

# function to check Neon Number

def checkNeon (x) :

    # storing the square of x

    sq = x * x

      

    # calculating the sum of sum of digits

    # of sqr

    sum_digits = 0

    while (sq != 0) :

        sum_digits = sum_digits + sq % 10

        sq = sq / 10

      

    return (sum_digits == x)

  

# Driver Code

  

i = 1

# Printing Neon Numbers upto 10000

while i <= 10000 :

    if (checkNeon(i)) :

        print i,

    i = i + 1

Answer 2

Program

temp = 0

pro = 0

for i in range(0,10001,1):

   temp = i * i

   while temp > 0:

       pro = pro + (temp % 10)

       temp = int(temp / 10)

   if i == pro:

       print(i)

   pro = 0

   i = i +1

Output

0

1

9

Explanation

• First i initialized a for loop upto 10000 number
• then i took the value of i for each iteration
• and multiplied it by itself
• and calculated the sum of digits in the multiplied number
• and i wrote an if condition to check whether the sum i got is equal to the number i took in for loop
• if true i wrote a print statement to print that number
• else it will loop until the condition false at 10001

---Hope this Helps  :)