Question

# Python program to check if the input year is a leap year or not

year = 2000

# To get year (integer input) from the user
# year = int(input("Enter a year: "))

if (year % 4) == 0:
if (year % 100) == 0:
if (year % 400) == 0:
# if block of 400
print("{0} is a leap year".format(year))
else:
# else block of 400
print("{0} is not a leap year".format(year))
else:
# else block of 100
print("{0} is a leap year".format(year))
else:
# else block of 4
print("{0} is not a leap year".format(year))​

Answer 1

Answer:

Wrong written

Explanation: