python program to check whether the string is symmetrical or palindrome.
Answers
Answer:
def palindrome(a):
# finding the mid, start
# and last index of the string
mid = (len(a)-1)//2
start = 0
last = len(a)-1
flag = 0
# A loop till the mid of the
# string
while(start<mid):
# comparing letters from right
# from the letters from left
if (a[start]== a[last]):
start += 1
last -= 1
else:
flag = 1
break;
# Checking the flag variable to
# check if the string is palindrome
# or not
if flag == 0:
print("The entered string is palindrome")
else:
print("The entered string is not palindrome")
# Function to check whether the
# string is symmetrical or not
def symmetry(a):
n = len(a)
flag = 0
# Check if the string's length
# is odd or even
if n%2:
mid = n//2 +1
else:
mid = n//2
start1 = 0
start2 = mid
while(start1 < mid and start2 < n):
if (a[start1]== a[start2]):
start1 = start1 + 1
start2 = start2 + 1
else:
flag = 1
break
# Checking the flag variable to
# check if the string is symmetrical
# or not
if flag == 0:
print("The entered string is symmetrical")
else:
print("The entered string is not symmetrical")
# Driver code
string = 'amaama'
palindrome(string)
symmetry(string)
Explanation:
explanation is given in the comments itself
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