Question

[Python] wap to transfer content from 1 list to 2 different list on the basis of odd and even indices. Elements at odd places in one list and the elements on even index in the other

Answer 1

Heya friend,

Here we go:

Before we move on to the code, let's understand this program first.

• Here we will take two empty lists odd and even in the beginning.
• We'll calculate the length of the primary list and work for that number of times.
• We will append the elements at the even index number to the list even and the element at the odd index number to the odd list using append function.
• If the index number is divisible by two, we can say it is even, else it is ought to be ought.

NOTE :- Keep in mind that the index number start from 0 .

Now let's move on to the code:

                     

                            SOURCE CODE

#to transfer content of a list to two different list based on their index numbers

a = eval(input('Enter any list:'))

odd=[]

even=[]

l=len(a)

for i in range (l):

   if i%2==0:

       even.append(a[i])

   else:

       odd.append(a[i])

print()

print('List containing elements from odd index position :',odd)

print()

print('List containing elements from even index position :',even)

                                 OUTPUT

Enter any list: [10,20,30,40,50,60]

List containing elements from odd index position : [20, 40, 60]

List containing elements from even index position : [10, 30, 50]

>>>

Enter any list: [3,6,5,9,2,7]

List containing elements from odd index position : [6, 9, 7]

List containing elements from even index position : [3, 5, 2]

>>>

Thanks !

#BAL #answerwithquality