Question

pz answer . Find the equivalent resistance across the two ends A and B of this circuit.
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Answer 1

Answer:

1 Ω

Explanation:

$R_{1}$ and $R_{2}$ are in parallel combination.

∴ Equivalent resistance between them is $(\frac{1}{2} + \frac{1}{2} )^{-1}$ = 1 Ω.

Let's call this $R_{a}$.

$R_{3}$ and $R_{4}$ are in parallel combination.

∴ Equivalent resistance between them is $(\frac{1}{2} + \frac{1}{2} )^{-1}$ = 1 Ω.

Let's call this $R_{b}$.

$R_{5}$ and $R_{6}$ are in parallel combination.

∴ Equivalent resistance between them is $(\frac{1}{2} + \frac{1}{2} )^{-1}$ = 1 Ω.

Let's call this $R_{c}$.

$R_{7}$ and $R_{8}$ are in parallel combination.

∴ Equivalent resistance between them is $(\frac{1}{2} + \frac{1}{2} )^{-1}$ = 1 Ω.

Let's call this $R_{d}$.

Now $R_{a}$ and $R_{b}$ are in series.

∴ Equivalent resistance between them is 1 + 1 = 2 Ω.

Let's call this $R_{x}$.

Also $R_{c}$ and $R_{d}$ are in series.

∴ Equivalent resistance between them is 1 + 1 = 2 Ω.

Let's call this $R_{y}$.

Now $R_{x}$ and $R_{y}$ are in parallel combination.

∴ Equivalent resistance across the two ends A and B of this circuit is $(\frac{1}{2} + \frac{1}{2} )^{-1}$ = 1 Ω.

Thanks !