Question

pz - qz=z^2 + ( x^2 + y^2)solve the partial differential equation​

Answer 1

Answer ccccc. brilliant

Answer 2

Answer:

(x^2/2z+y^2/2z+z/2,

Step-by-step explanation:

take multiplier as 1,1,1

and equate with dz/z^2+(x+y)^2

=xdx+ydy+zdz/z^2+(x+y)^2

then integrate on both side

you will get your one solution