Question

PZZZ HELP
k^2+64-k+7k^3

Answer 1

Step-by-step explanation:

Factories:k²+64-k+7k³

Solution:

Let p(k) = k²+64-k+7k³

Here, the constant term is 64.

Its factors are ± 1, ± 2, ± 8, etc.

By trial, put k = -2, we find that

p(-2) = (-2)²+64-(-2)+7(-2)³

= -4+128+2+63 = 0

.°. By factor theorem, x+2 is a factor of p(k)

Now,

=>

Answer 2

Step-by-step explanation:

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