Question

Q 01 . If Patm = 0 mm Hg and Palv = –2 mm Hg, then
(a) it is the end of the normal inspiration and there is no
airflow
(b) it is the end of the normal expiration and there is no
airflow
(c) transpulmonary pressure (Ptp) is –2 mm Hg
(d) air is flowing into the lungs.​

Answer 1

Answer:

A

Explanation:

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