Question

Q: 1.1 The specific heat capacity of water is 4.18J * K ^ - 1 * g ^ - 1 . Determine the enthalpy change when 10.00 g of water is heated from 285.0 to 300.0 K?​

Answer 1

Answer:

The specific heat capacity of water is 4.18J * K ^ - 1 * g ^ - .

hope it's help you

Answer 2

• Answer:627j
• Answer:627jExplanation:
• Answer:627jExplanation:H=mcAT
• Answer:627jExplanation:H=mcATAH=10*4.18*(300-285)
• Answer:627jExplanation:H=mcATAH=10*4.18*(300-285)ΔΗ=10*4.18*15
• Answer:627jExplanation:H=mcATAH=10*4.18*(300-285)ΔΗ=10*4.18*15ΔH=627j

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