Question

Q 1- A ball thrown vertically returns to the thrower after 10 seconds .Calculate

i) the velocity with which it was thrown up

ii) the maximum height it reaches, and

iii) it’s position after 7 seconds.
Please give the solution with explanation

Answer 1

Answer:

I) velocity with which it was thrown(u) =98m/s

ii) maximum height(h1) =390m

iii) position after 7s(h2) =445.9m

Explanation:

t1=10s

v=0m/s

g=9.8m/s

I) v=u-gxt1

0=u-9.8x10

u=98m/s

ii) h1=utxt1-1/2xgx(t1) ^2

=98x10-1/2x9.8x(10) ^2

=980-490

=390m

iii) h2=uxt2-1/2xgx(t2) ^2

=98x7-1/2x9.8x(7) ^2

=686-240.1

=445.9m