Question

Q.1 A capacitor of 4 uF is connected as shown in the circuit. The internal
resistance of the battery is 0.512. The amount of charge on the capacitor
plates will be a)0
(b) 4u
(c) 16uC
(d) 8 uc​

Answer 1

Answer:

8uc

Explanation:

current flows through 2ohms resistance from left to right

the potential difference across 2ohms resistance v=IR=1*2=2

I=v/R+r=2.5/2+0.5=1

since capacitor is parallel with 2ohms so it is also has 2V potential difference across it.

the charge on capacitor

q=CV=2uF*2V

=8uc