Question

Q.1)A copper rod of diameter 1cm and length 8cm is drawn into a wire of length 18m of uniform thickness.Find the thickness of the wire.
Q.2)A cone of height 24cm and radius of base 6cm is made up of modelling clay.A child reshapes it in the form of a sphere.Find the radius of the sphere.
Q.3)A metallic sphere of radius 4.2 cm is melted and recast into the shape of a cylinder of radius 6 cm. Find the height of the cylinder.
Q.4)Metallic spheres of radii 6 cm, 8 cm and 10 cm, respectively, are melted to form a single solid sphere. Find the radius of the resulting sphere.
Q.5)A 20 m deep well with diameter 7 m is dug and the earth from digging is evenly spread out to form a platform 22 m by 14 m. Find the height of the platform.
Q.6)A well of diameter 3 m is dug 14 m deep. The earth taken out of it has been spread evenly all around it in the shape of a circular ring of width 4 m to form an embankment. Find the height of the embankment.
Q.7)A container shaped like a right circular cylinder having diameter 12 cm and height 15 cm is full of ice cream. The ice cream is to be filled into cones of height 12 cm and diameter 6 cm, having a hemispherical shape on the top. Find the number of such cones which can be filled with ice cream.
Q.8)A cylindrical bucket, 32 cm high and with radius of base 18 cm, is filled with sand. This bucket is emptied on the ground and a conical heap of sand is formed. If the height of the conical heap is 24 cm, find the radius and slant height of the heap.
Q.9)Water in a canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. How much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?
Q.10) A farmer connects a pipe of internal diameter 20 cm from a canal into a cylindrical tank in her field, which is 10 m in diameter and 2 m deep. If water flows through the pipe at the rate of 3 km/h, in how much time will the tank be filled?

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Answer 1

Answer:

The volume of the rod = π×( 1/2) ^2×8=2π cm^3

The length of the new wire of the same volume = 18 m = 1800 cm

If r is the radius ( in cm ) of cross-section of the wire, its volume = π×r^2×1800 cm^3

Therefore,

π×r^2×1800=2π

r^2= 1/900

r= 1/30

So, the diameter of the cross section, i.e., the thickness of the wire is 1/15 cm, i.e., 0.67 mm (approx.)

Please mark me as BRAINLIEST.

Answer 2

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