Math, asked by akbarkhan10708, 27 days ago

Q. 1. (A) Four alternative answers are given for each of the following subquestions.
Choose the correct alternative and write the alphabet of that answer:
(iv) The areas of two similar triangles are 9 cm² and 16 cm². The ratio of their
corresponding heights is
(A) 9:16
(B) 3:4 (C) 4:3
(D) 16:9​

Answers

Answered by Anonymous
2

Answer:

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Step-by-step explanation:

Given: Area of two triangle are 9cm² and 16cm²

To find: Ratio of their corresponding sides

 \large\frac{ar(∆1)}{ar(∆2)}  = ( \frac{side 1}{side2})  {}^{2}  \\  \\ \large \frac{9}{12}  = ( \frac{side 1}{side2})  {}^{2} \\  \\ \large  \sqrt{\frac{9}{12}}   =  \sqrt{( \frac{side 1}{side2})  {}^{2}}  \\  \\ \large\therefore \frac{side1}{side2}  =  \frac{3}{4}

So, the ratio of their corresponding sides is 3 : 4

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