Q.1 A girl of mass 40 kg jumps with a horizontal velocity of 5 m s-1 onto a stationary cart with frictionless wheels. The mass of the cart is 3 kg. What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction. Please explain what you are doing by writing the equations first (like p = ma)
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hope this will help you
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-sneha
love to help
any further doubt ask me anytime
please like my answer if it is helpful
thank you
-sneha
love to help
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Amaninder24:
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yaa
i m a ncert student
that pic was from my book
Nice! Thanks!
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Net external forces on the system is zero hence we can apply conservation of momentum on the system
Initial momentum : 40 * 5(mass of girl* her velocity)
Now since girl is in the cart the velocities of girl and cart is equal
So final momentum = 40*v + 3*v (where v is the final velocity of the girl and cart)
43v = 200 (conservation of momentum)
V = 200/43m/s
V = 4.65m/s
Initial momentum : 40 * 5(mass of girl* her velocity)
Now since girl is in the cart the velocities of girl and cart is equal
So final momentum = 40*v + 3*v (where v is the final velocity of the girl and cart)
43v = 200 (conservation of momentum)
V = 200/43m/s
V = 4.65m/s
Thanks!
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