Question

Q-1) A shot - putt is a metallic sphere of radius 4.9 CM. if the density of the metal is 7.8 g per cm³, find the mass of the shot - putt.

Q-2) A hemispherical bowl has a radius of 3.5 cm.what would be the volume of water it would contain ?




​

Answer 1

Question : 1

A shot - putt is a metallic sphere of radius 4.9 CM. if the density of the metal is 7.8 g per cm³, find the mass of the shot - putt.

★ Given :

• Radius of metallic sphere is 4.9 cm.
• Density of metal is 7.8 g per cm³.

★ To Find :

• Mass of the shot - putt ?

★ Solution :

First, we need to find the volume of the sphere.

◆ We know that,

↳Volume of a sphere = 4 / 3 πr³

= 4 / 3 × 22 / 7 × 4.9 × 4.9 × 4.9 cm³

= 493 cm³ ( nearly )

Further, mass of 1 cm³ of metal is 7.8 g.

Therefore, mass of the shot - spot = 7.8 × 493 g

= 3845.44 g = 3.85 Kg ( nearly ).

■ Hence, the mass of the shot - putt is 3.85 Kg ( nearly ).

_____________________

Question : 2

A hemispherical bowl has a radius of 3.5 cm.what would be the volume of water it would contain ?

★ Given :

• Radius of hemispherical bowl is 3.5 cm.

★ To Find :

• What would be the volume of water it would contain ?

★ Solution :

◆ We know that,

↳ Volume of a Hemisphere = 2 / 3 πr³

The volume of water the bowl can contain

= 2 / 3 × 22 / 7 × 3.5 × 3.5 × 3.5 cm³

= 89.8 cm³

■ Hence, the volume of water it would contain is 89.8 cm³.

Answer 2

Question - 1

• A shot - putt is a metallic sphere of radius 4.9 CM. if the density of the metal is 7.8 g per cm³ , find the mass of the shot - putt.

Given :-

• Radius of metallic sphere is 4.9 cm.
• Density of metal is 7.8 g per m³.

To find :-

• Mass of the shot - putt ?

Solution :-

• First, we need to find the volume of the sphere.

★ We know that ★

→ Volume of sphere = 4/3 πr³

= 4/3 × 22/7 × 4.9 × 4.9 × 4.9 cm³

= 4.9 cm³ ( nearly )

Further, mass of 1 cm³ of metal is 7.8 g.

Therefore, mass of the shot - spot = 7.8 × 493 g

= 3845.44 g = 3.85 kg ( nearly )

Hence,

• The mass of the shot - putt is 3.85 kg ( nearly ).

________________________________

Question - 2

• A hemisphere bowl has a radius of 3.5 cm. What would be the volume of water it would contain.

Given :-

• Radius of hemisphere bowl is 3.5 cm.

To find :-

• What would be the volume of water it would contain ?

Solution :-

★ We know that ★

→ Volume of a Hemisphere = 2/3 πr³

The volume of water the bowl can contain.

= 2/3 × 22/7 × 3.5 × 3.5 × 3.5 cm³

= 89.9 cm³

Hence,

• The volume of water it would contain is 89.9 cm³.