Q.1 A truck moving with a speed of 35 m/s stops after 7 seconds when breaks are applied. Calculate
the acceleration produced in the truck.
Answers
Answered by
6
v=0m/s
u=35m/s
t=7s
a=(v-u)/t
a=0-35/7=-5m/s^2
The negative sign is because of the deceleration.
Answered by
1
Answer:
a = -5m/s^2 is right answer
Similar questions