Q.1: ABCD is a quadrilateral in which AD = BC and ∠DAB = ∠CBA. Prove that (i) ΔABD ≅ ΔBAC (ii) BD = AC (iii) ∠ABD = ∠BAC. 
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In △ABD and △BAC,
AD=BC (Given)
∠DAB=∠CBA (Given)
AB=BA (Common)
∴△ABD≅△BAC (By SAS congruence rule)
∴BD=AC (By CPCT)
And, ∠ABD=∠BAC (By CPCT)
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Answered by
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In △ABD and △BAC,
AD=BC (Given)
∠DAB=∠CBA (Given)
AB=BA (Common)
∴△ABD≅△BAC (By SAS congruence rule)
∴BD=AC (By CPCT)
And, ∠ABD=∠BAC (By CPCT)
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