Q.1.Bisectors of angles A, B and C of a triangle ABC intersect its circumcircle at D, E and F respectively. Prove that the angles of the triangle DEF are 90° – (½)A, 90° – (½)B and 90° – (½)C.
Q.2.In any triangle ABC, if the angle bisector of ∠A and perpendicular bisector of BC intersect, prove that they intersect on the circumcircle of the triangle ABC.
Q.3: Prove that the circle drawn with any side of a rhombus as diameter passes through the point of intersection of its diagonals.
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Question:- 1
Given :-
- Bisectors of angles A, B and C of a triangle ABC intersect its circumcircle at D, E and F respectively.
To Prove :-
- The angles of the triangle DEF are 90° – (½)A, 90° – (½)B and 90° – (½)C.
Proof :-
- Please find the attachment number 1
Question : - 2
Given :-
- In triangle ABC, the angle bisector of ∠A and perpendicular bisector of BC intersect at D.
To prove :-
- D lies on the circumcircle of the triangle ABC.
Construction :-
- Join OB and OC.
Proof :-
- Please find the attachment number 2
Question :- 3
Given :-
- A rhombus ABCD in which a circle is drawn taking AB as diameter. Diagonal AC and BD intersects at O.
To Prove :-
- Circle drawn on AB as diameter passes through O.
Proof :-
Given that
- ABCD is a rhombus having diagonals AC and BD intersect each other at O.
We know,
- Diagonals of rhombus bisect each other at right angles.
Since
Additional Information :-
1. Angle in same segments arw equal.
2. Angle in semi-circle is 90°.
3. Angle subtended at the centre of a circle by an arc is double the angle subtended by the same arc on the circumference.
4. Perpendicular bisector of a chord of a circle passes through centre.
5. Equal chords are equidistant from centres.
6. Equal chords subtends equal angles at centre.
Attachments:
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