Question

​Q.1 By applying kirchhoff's law measure the current in 8ohm​

Answer 1

Answer:

by using the kirchoffs law ,

total resistance is :

4+8 = 12 Ω

net resistance

1/R = 1/12 + 1/2 + 1/4 + 1/4 + 1/2

R = 220 V

The poteintial = 32V

uing the ohm s law = V = IR

I = 220 /32  

I = 6.8

hence the current in 8 Ω is 6.8A                  

Answer 2

Answer:

current : 6.8A

Explanation:

given = current = 80Ω

solution =

 apply the kirchoff"s law ;

find the resistance

∴4 + 8 = 12Ω

now for the net resistance:

∴1/R = 1/12 + 1/2 + 1/4 + 1/4 +  1/2

R = 220V

so, the potential = 32V(by the sumof all three  batteries)

∴now  apply the using ohm"s law

V =  IR

I=V/R

I =  220 / 32

I =  6.8 A.

the current in 8Ω is 6.8A