Question

Q.1.cards with two digit numbers are placed in a box and mixed well
find the probablity is getting.
1. a multiple of 6 ?
2. a number with some digits ?​

Answer 1

$Two \:digit \: numbers \: are \: 10,11,12,\cdot\cdot\cdot \\98,99$

$Total \:cards \: in \:the \:box \\= 99 - 10 + 1 \\= 90$

$Number \:of \\ total \: possible \: outcomes = 90 \: --(1)$

$multiples \:of \: 6 \:in \: the \\box = { 12,18,24, \cdot \cdot \cdot , 96 }</p><p>[tex] Number \:of \: multiples \:of \: 6 \:in \: the \\box = 15$

$Number \:of \: favourable \: outcomes = 15 \:--(2)$

$P(a \: multiple \:of \:6) = \frac{(2)}{(1)} \\= \frac{15}{90} \\= \frac{1}{6}$

Therefore.,

$\red {P(a \: multiple \:of \:6)}\green {= \frac{1}{6}}$

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