Question

Q.1 Choose the correct option -
(i) Square of 3x - 4y is
a)
${9x}^{2} - {16y}^{2}$
b)
${6x}^{2} - {8y}^{2}$
c)
${9x}^{2} + {16y}^{2} + 24xy$
d)
${9x}^{2} + {16y}^{2} - 24xy$

Q.2 Verify the following -
a) (ab + bc)(ab - bc)+(bc + ca)(bc - ca)+(ca + ab)(ca - ab) = 0
b)
$(m + n)( {m}^{2} - mn + {n}^{2} ) = {m}^{3} + {n}^{3}$

Q.3 Simplify-
a)
$(a - b)( {a}^{2} + {b}^{2} + ab) - (a + b)( {a}^{2} + {b}^{2} - ab)$
b)
$( \frac{3}{2} {p}^{2} + \frac{2}{3} {q}^{2} )( {2p}^{2} - {3q}^{2} )$
Hii guys please help me !!
it took me almost 15 mins to write this
I will mark brainliest the dust answer!!



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Answer 1

Answer:

1)a,

2a)(ab+bc)(ab-bc)+(bc+ca)(bc-ca)+(ca+ab)(ca-ab)=0

=(ab(ab-bc) +bc (ab-bc)) +(bc (bc-ca) +ca (bc-ca)) +(ca(ca-ab) +ab(ca-ab)) =0

=(ab^2-ab^2c+ab^2c-bc^2)+(bc^2-bc^2a++bc^2a-ca^2)+(ca^2-ca^2b +a^2bc-ab^2)=0

=now cancel negative and positive signs

=0=0