Q-1 Draw a distance - time graph from the below given information and answer the questions
given below.
(5)
TIME(HOUR) 0 2 4 8 12
DISTANCE(KM) 0 50 150 150 250
1. What type of motion is observed in the substance during the time duration of 0 to 4
hours?
2. During which time duration is the substance seen in stable state?
Answers
Answer:
a-1 ) uniform motion
A-2 ) 4 to 8 hours
Explanation:
sorry for that
Given :
Time Hr 0 2 4 8 12
Distance km 0 50 150 150 250
To Find : What type of motion is observed in the substance during the time duration of 0 to 4
2. During which time duration is the substance seen in stable state?
Solution:
Time 0 Distance 0
Time 2 Distance 50
Average Speed = (50 - 0)/(2 - 0)= 25 km/hr
Time 2 Distance 50
Time 4 Distance 150
Average Speed = (150 - 50)/(4 - 2)= 50 km/hr
Hence Non Uniform motion during the time duration of 0 to 4
Time 4 Distance 150
Time 8 Distance 150
Average Speed = (150 - 150)/(8 - 4)= 0 km/hr
At REST
Substance is in stable state during the time duration of 4 to 8
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