Q-1 examine which of the following pairs of triangle are congruent:- ∆PQR: PQ=5m,∆XYZ: XY=5m, PR=4m, angle P=90° YZ=4m, angle Y=90°
Answers
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3}
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 3
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3}
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3} 3
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3} 31
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3} 31
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3} 31 n - 27 n = 81 + 1
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 81to find outvalue of nsolutionin the given equation we have 1 unknown value value i.e n3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 = 8127 n + \frac{1}{3} 31 n - 27 n = 81 + 1here now we will cancel out +27 n with -27 n
value of n is 246Step-by-step explanation:given term3n × 9n + \frac{1}{3} 31 n - 1 × 27 n - 1 =