Q.1. explain the process of conduction of nerve impulses upto development of action potential
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Answer:
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A nerve impulse is the electric signals that pass along the dendrites to generate a nerve impulse or an action potential. ... Conduction of nerve impulse occurs due to the presence of active and electronic potentials along the conductors. Transmission of signals internally between the cells is achieved through a synapse.
Answer:
(1) The origin and maintenance of resting potential depends on the original state of no stimulation.
(2) Any stimulus or disturbance to he membrane will make the membrane permeable to Na^+ ions. This causes rapid influx of Na^+ ions.
(3) The voltage gated Na^+/K^+ channels are unique. They can change the potential difference of the membrane as per the stimulus received and also the gales operate separately and are self closing
(4) During resting potential, both gates are closed and resting potentlal is maintained.
(5) However during depolarization, the Na channels open but not the K^+ channels. This causes Na^+ to rush into the axon and bring about a depolarisation. This condition is called action potential.
(6) Extra cellular fluid (ECF) becomes electronegative with respect to the inner membrane which becomes electropositive.