Question

Q 1:Factorize
(i)6x²+x-2​

Answer 1

$6x ^{2} + x - 2$

$6x^{2} + (4 - 3)x - 2$

$6x ^{2} + 4x - 3x - 2$

$2x(3x + 2) - 1(3x + 2)$

$(2x - 1)(3x + 2)$

Answer 2

Step-by-step explanation:

see when we use factorisation method we need to find the product and sum so

Product= ac= 6x-2= -12

sum = mid value of the equation= X which means 1

no.s are= LCM of the product= 2x2x3

Now we need to find two numbers from using LCM of the product by which the product of the numbers will be equal to -12 and Thier sum is +X

no.s are = 4x, -3x

now we will spilt the mid value