Q.1) Find refractive index of glass,if the speed of light in glass is 2×10⁸ and speed of light in air is 3×10⁸ m/s.
2)The far point of a myopic person is 150 cm in front of the eye.Calculate the focal length and the power of a lens required to enable him to see distant object clearly ?
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refractive index of glass n=(speed of light in air)/(speed of light in glass)
n=c/v
n=3*100000000/2*100000000
n=3/2
n=1.5 (refractive index of water) Ans.
n=c/v
n=3*100000000/2*100000000
n=3/2
n=1.5 (refractive index of water) Ans.
asr1:
is this a correct ans
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