Math, asked by attaullahrabbani1000, 9 months ago

► Q#1 Find the derivative with respect to t of following
(a)
v = (5t-2 + 3t2)3
(b)
v= 2t-2 – 3t-1 + 4 + 5t
(c)
v = (6t - 2)-0.5

Answers

Answered by adityachoudhary138
0

Answer:

Find dy/dx in terms of t for the curve defined by the parametric equations: x = (t-1)^3, y = 3t - 8/t^2, where t≠0. The first step is to recognise that, by the chain rule, dy/dx = dy/dt * dt/dx. dy/dt and dt/dx can both be found by differentiating the functions given in the question, to give dy/dt and dx/dt.

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