Question

Q. 1. Find the distance between the following points :
(4,3, -6) and (-2, 1, -3).

please help me...
support..

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Answer 1

Answer:

Step-by-step explanation:

√[{4-(-2) ]^2}+(3-1) ^2+{-6+3}]

=√[6^2+2^2+(-3) ^2]

Answer 2

Answer:

7 units is the distance between from (4,3, -6) and (-2, 1, -3)

Step-by-step explanation:

Explanation:

Given in the question that, (4 , 3, -6) and (-2 ,1 ,-3)

• Distance is a measure of how far apart two objects or locations are using numbers.
• Distance can refer to a physical length in physics or to an estimate based on other factors in common usage.

And the distance formula,

D = $\sqrt{(x_2-x_1)^2 + (y_2- y_1)^2 +(z_2 - z_1)^2}$

Step 1:

From the given question we have,

$x_1 = 4 , y_1 = 3 , z_1 = -6 \ and\\ \ x_2= -2 , y_2 = 1 , z_3 = -3$

Now, from the distance formula,

D = $\sqrt{(x_2-x_1)^2 + (y_2- y_1)^2 +(z_2 - z_1)^2}$

⇒D = $\sqrt{(-2 -4)^2 +(1-3)^2 +(-3+6)^2}$

⇒D = $\sqrt{(-6)^2+(-2)^2+(3)^2}$ = $\sqrt{36 +4 + 9}$

D = $\sqrt{49}$= 7units.

Final answer:

Hence, 7 units is the distance between (4,3, -6) and (-2, 1, -3).

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